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Lorentz contraction |
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| Nov15-09, 06:24 PM | #52 |
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Recognitions:
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Lorentz contraction |
| Nov15-09, 06:25 PM | #53 |
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Matheinste. |
| Nov15-09, 06:27 PM | #54 |
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| Nov15-09, 06:43 PM | #55 |
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Yet, the launch frame does not see it this way. It sees the distance as constant. How is this so? |
| Nov15-09, 06:59 PM | #56 |
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| Nov15-09, 07:05 PM | #57 |
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Isn't length contraction a phenomena of the "at rest" frame when viewing the moving frame? |
| Nov15-09, 07:28 PM | #58 |
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We have four rockets all with identical solid fuel propellants that burn at a fixed rate for a fixed length of time. Rocket A and B are joined by a tough cable of length d and rockets C and D are separated by a distance of d but not physically connected. All 4 rockets launch simultaneously in the launch frame. When they have exhausted their fuel rockets C and D are still a distance d apart, but rockets A and B are less than d apart. Rockets A and B have been physically pulled closer together by the length contraction of the cable. If a fifth rocket and observer was introduced and this time only the fifth observer accelerated, then distances between the unconnected and connected rocket pairs would appear to length contract equally, but the apparent length contraction of the gap between the unconnected rockets is not physical. The changes in the clock rates and ruler lengths of the fifth observer makes the gap appear to contract. |
| Nov15-09, 07:32 PM | #59 |
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| Nov15-09, 07:35 PM | #60 |
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The rest frame does not see the gap getting wider. |
| Nov15-09, 07:38 PM | #61 |
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This thought experiment changes the game. It should be solvable in the context we were in. If the string contracts from the rest observer and the distance does not change, does this imply space does not contract but rods do? |
| Nov15-09, 07:52 PM | #62 |
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| Nov15-09, 07:59 PM | #63 |
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Assuming your post though, how do you explain this? We have the rest frame not seeing any distance differentials. We have the accelerating frames getting further apart in their context. How do you reconcile this? |
| Nov15-09, 08:31 PM | #64 |
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We know y < z. That is Lorentz contraction. We also know x = y. ("We have the rest frame not seeing any distance differentials. ") Therefore z > x. ("We have the accelerating frames getting further apart in their context.") |
| Nov15-09, 08:50 PM | #65 |
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In order to compare these like this, you must have a uniform space. You are depending on the trichotomy of the real numbers but the spaces are not the same in the frame to frame analysis. Do you compare these another way I am not seeing? |
| Nov16-09, 02:49 AM | #66 |
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| Nov16-09, 04:24 AM | #67 |
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| Nov16-09, 02:04 PM | #68 |
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