Register to reply

Find the Area of the Interior

Share this thread:
mmmboh
#1
Feb15-10, 02:32 PM
P: 408
Find a parametrization of the curve x2/3+y2/3=1 and use it to
compute the area of the interior.

What I did was y=(1-x2/3)3/2

I then integrated this function from 0 to 1 (using maple since it is a crazy integral) and got the answer to be 3/32 [tex]\pi[/tex].

However this is wrong, I probably wasn't suppose to do it the way I did anyway considering that the integral is so complicated.

So what should I do? I am learning Green's theroem right now if that helps, although I may have skipped ahead in it a bit I'm not sure.

Thanks.

Edit: Hm ok I have figured out what to do, the answer is 3/8 pi. How come my original answer is 1/4 of this though?
Phys.Org News Partner Science news on Phys.org
Hoverbike drone project for air transport takes off
Earlier Stone Age artifacts found in Northern Cape of South Africa
Study reveals new characteristics of complex oxide surfaces
tiny-tim
#2
Feb15-10, 04:15 PM
Sci Advisor
HW Helper
Thanks
tiny-tim's Avatar
P: 26,160
Hi mmmboh!
Quote Quote by mmmboh View Post
Find a parametrization of the curve x2/3+y2/3=1
They want you to use a parametrisation.

For example, if it were x2+y2=1, you'd use x = cosθ, y = sinθ.


Register to reply

Related Discussions
Using Area to Find Dimensions General Math 3
Help~find the interior, boundary, closure and accumulation points of the following. Calculus 5
How do i find the area General Math 1
Find area... Introductory Physics Homework 3
Find the area... General Math 2