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Integral of sin(2x)dx 
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#1
Apr410, 09:09 PM

P: 33

1. The problem statement, all variables and given/known data
[tex]\int[/tex] sin(2x)dx 2. Relevant equations I know the integral of sin(x)dx = cos(x) + C 3. The attempt at a solution What I did was to say that the integral is cos(2x) +C, which isn't the correct answer...I should have gotten 1/2(cos(2x)) +C. I can see that this is the correct answer when I differentiate it via chain rule and get sin(2x), however I can't seem to integrate the problem to get the right answer. Can someone walk me through it please..... 


#2
Apr410, 09:35 PM

Mentor
P: 21,251

Use substitution, with u = 2x, du = 2dx. Integration by substitution is the reverse of the chain rule in differentiation.



#3
Apr410, 09:49 PM

P: 33

ah so that's where I went wrong....I tried u substitution but I used u=sin2x instead of u=2x. thanks mark44.



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