# Triple Integral in Spherical Coordinates

by cepheid
Tags: coordinates, integral, spherical, triple
 Mentor P: 5,190 I have a hemispherical surface of radius R with it's base centred on the origin. We are using the convention: r is the radius i.e. the magnitude of the position vector of a point: its distance from the origin. theta is the polar angle phi is the azimuthal angle I am asked to calculate the integral of the divergence of a given vector field v over this volume (enclosed by the hemisphere). So far what I have done is to say that a full sphere would be given by the equation: r = R What about a hemisphere? It seems to me that the angle theta must be restricted so that points below the x-y plane are not part of the domain. So what are the allowed values of theta? I can't seem to figure out whether it should be -pi/2 < theta < pi/2, or something else? I need to know this to set my bounds of integration for one of the three integrals. Thanks.
 P: 4,003 For a hemisphere : r goes from 0 to R theta goes from : 0 to 90° phi goes from : 0 to 360° Ofcourse, you know that you need to express the angles in radials regards marlon

 Related Discussions Calculus & Beyond Homework 3 Calculus & Beyond Homework 5 Introductory Physics Homework 2 Introductory Physics Homework 3 Introductory Physics Homework 5