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failure rate of a system at time 't' |
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| Mar21-11, 07:36 PM | #1 |
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failure rate of a system at time 't'
I need to solve the following problem for a school assignment.
Let λ(t) denote the failuer rate of a system at time 't'. The failure rate is simple the number of failures in unit time. For example, if the unit time is one day, then λ is the average of failures per day. Let μ(t) denote the total number of failures from the first release (time t=0) until the current time, 't'. Then we have (1) λ= dμ/dt (2) μ = ∫λ(T) where the limits of integration are T=0 (lower) and T=t (upper) Two models are used for estimating λ and μ. In the forumlae below, λ0 is the failure rate at time t=0, and α and β are constants λ=λ0(1-μ/α) λ=λ0e^- β μ Use (1) or (2) to find λ and μ as functions of time for each model. .....I just need some direction. Thanks! |
| Mar21-11, 07:56 PM | #2 |
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[tex]\lambda = \lambda_0 \left(1-\frac{\mu}{\alpha}\right)[/tex] You should be able to substitute λ=dμ/dt and get a seperable differential equation in μ. Then you differentiate that equation to get λ. So you just need to solve: [tex]\frac{d\mu}{dt} = \lambda_0 \left(1-\frac{\mu}{\alpha}\right)[/tex] |
| Mar21-11, 08:06 PM | #3 |
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so i just differentiate with respect to μ?
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| Mar21-11, 09:46 PM | #4 |
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failure rate of a system at time 't'
so the resulting integration would be:
-α ln (μ -α) evaluated at 0 and 't' correct? |
| Mar21-11, 10:05 PM | #5 |
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Well, don't EVALUATE it at those two points. Instead, set that equal to t+C.
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| Mar21-11, 10:22 PM | #6 |
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francis has started two threads for the same question. another thread at
http://www.physicsforums.com/showthread.php?t=483125 I am answering the same question at this thread. Beware francis |
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