Register to reply 
A balanced wye delta connection.. 
Share this thread: 
#1
Jul711, 04:59 AM

P: 5

1. The problem statement, all variables and given/known data
A balanced delta load having 18ohm resistance and 24 capacitive reactance in series in each phase is supplied through lines each having 1 ohm resistance and 2 ohm inductive reactance. If the line to line voltage at the sending end is 250 V, find the phase current and line currents. 2. Relevant equations Zy = 1/3 Z delta 3. The attempt at a solution i first convert the delta load to wye so the load now becomes Zy= (6j8) and then i add the line impedance and load impedance...Zeq= (6j8)+ (1+j2) = 7j6 and then i solved for the line currents and phase currents which is equal for wye Ip=Il= 144.34/ 9.22 angle of 40.60 it's answer is 15.66 angle of 40.60 degrees...THIS IS WHERE I AM CONFUSED HOW DO I SOLVE THE PHASE CURRENTS AND LINE CURRENTS WHEN THE LOAD IS IN DELTA...it is not supposed to be equal since the load is in delta...please help ... 


Register to reply 
Related Discussions  
Question about balanced wye  delta connection..  Electrical Engineering  1  
Delta wye connection using 3 small transformers  Electrical Engineering  5  
Spin connection vs. Christoffel connection  High Energy, Nuclear, Particle Physics  3  
Balanced equations  Chemistry  5  
Balanced Lines...?  Electrical Engineering  1 