Jul7-11, 04:59 AM
1. The problem statement, all variables and given/known data
A balanced delta load having 18ohm resistance and 24 capacitive reactance in series in each phase is supplied through lines each having 1 ohm resistance and 2 ohm inductive reactance. If the line to line voltage at the sending end is 250 V, find the phase current and line currents.
2. Relevant equations
Zy = 1/3 Z delta
3. The attempt at a solution
i first convert the delta load to wye so the load now becomes Zy= (6-j8) and then i add the line impedance and load impedance...Zeq= (6-j8)+ (1+j2) = 7-j6 and then i solved for the line currents and phase currents which is equal for wye Ip=Il= 144.34/ 9.22 angle of -40.60
it's answer is 15.66 angle of 40.60 degrees...THIS IS WHERE I AM CONFUSED HOW DO I SOLVE THE PHASE CURRENTS AND LINE CURRENTS WHEN THE LOAD IS IN DELTA...it is not supposed to be equal since the load is in delta...please help ...
|Register to reply|
|Question about balanced wye - delta connection..||Electrical Engineering||1|
|delta wye connection using 3 small transformers||Electrical Engineering||5|
|Spin connection vs. Christoffel connection||High Energy, Nuclear, Particle Physics||3|
|Balanced Lines...?||Electrical Engineering||1|