Balanced Y-connected 3-phase load

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In summary, for a balanced 3 phase supply of VRMS = 6599.1V applied to a balanced load with three identical impedances of Z = 50<37°, the phase voltages are Van = 3810<0, Vbn = 3810<-120, and Vcn = 3810<-240. The phase currents are Ian = 76.2<-37, Ibn = 76.2<-157, and Icn = 76.2<-277. The total active power supplied to the load is approximately 695490W and the total reactive power is approximately 524090VAR. These values may vary slightly depending on calculations.
  • #1
eehelp150
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Homework Statement


A balanced 3 phase supply of VRMS = 6599.1V is applied to a balanced Y-connected 3-phase load consisting of three identical impedances Z = 50<37°. Take the phase-to-neutral voltage Van as the reference. Calculate:

A)Phase voltages Van, Vbn, Vcn
B)Phase currents Ian, Ibn, Icn
C)Total active and reactive power supplied to load
upload_2016-10-26_20-26-45.png

Homework Equations


upload_2016-10-24_23-23-24-png.107967.png


The Attempt at a Solution


A)
6599.1V/sqrt(3) = 3810
Van = 3810<0
Vbn = 3810<-120
Vcn = 3810<-240

B)

Ian = 3810<0/50<37° = 76.2<-37
Ibn = 76.2<-157
Icn = 76.2<-277

Did I do parts A and B correctly?
 
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  • #2
eehelp150 said:

Homework Statement


A balanced 3 phase supply of VRMS = 6599.1V is applied to a balanced Y-connected 3-phase load consisting of three identical impedances Z = 50<37°. Take the phase-to-neutral voltage Van as the reference. Calculate:

A)Phase voltages Van, Vbn, Vcn
B)Phase currents Ian, Ibn, Icn
C)Total active and reactive power supplied to load
View attachment 108042

Homework Equations


upload_2016-10-24_23-23-24-png.107967.png


The Attempt at a Solution


A)
6599.1V/sqrt(3) = 3810
Van = 3810<0
Vbn = 3810<-120
Vcn = 3810<-240

B)

Ian = 3810<0/50<37° = 76.2<-37
Ibn = 76.2<-157
Icn = 76.2<-277

Did I do parts A and B correctly?
Yes.
 
  • #3
cnh1995 said:
Yes.
For total active power, I got:
695490W
For total reactive power, I got:
524090VAR
Would you mind double checking?
 
  • #4
eehelp150 said:
For total active power, I got:
695490W
For total reactive power, I got:
524090VAR
Would you mind double checking?
I am getting values close to yours, just a difference of a few watts.
P=√3VLIcosΦ.
Q=√3VLIsinΦ.
Φ=37°.
 

Related to Balanced Y-connected 3-phase load

1. What is a balanced Y-connected 3-phase load?

A balanced Y-connected 3-phase load is an electrical circuit that is connected in a Y or star configuration, where each phase is connected to a common neutral point. The load is considered balanced when the impedance values of each phase are equal.

2. How do you calculate the total impedance of a balanced Y-connected 3-phase load?

The total impedance of a balanced Y-connected 3-phase load can be calculated by using the formula Ztotal = Zphase / √3, where Zphase is the impedance of each individual phase. This formula takes into account the phase angles of the three phases in the Y-configuration.

3. What are the advantages of using a balanced Y-connected 3-phase load?

One advantage of using a balanced Y-connected 3-phase load is that it allows for the transmission of larger amounts of power with a lower voltage, reducing the cost of transmission lines and equipment. It also provides a more stable and efficient distribution of power compared to a single-phase load.

4. How does a balanced Y-connected 3-phase load affect power quality?

A balanced Y-connected 3-phase load can improve power quality by reducing voltage drops and minimizing harmonics in the power system. It also helps to balance the load on each phase, reducing the risk of overload and voltage fluctuations.

5. What are some common applications of a balanced Y-connected 3-phase load?

A balanced Y-connected 3-phase load is commonly used in industrial and commercial settings for powering large motors, air conditioning units, and other heavy machinery. It is also used in power distribution systems to deliver electricity to residential and commercial buildings.

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