Find a Vector parallel to the line of intersection

stratusfactio
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Homework Statement


Find a vector parallel to the line of intersection of the planes given by the equations 2x-3y+5z=2 and 4x+y-3z=7.


Homework Equations


How do I go about this? I know we have two vectors <2,3,5> and <4,1,-3> but where do I go from here?


The Attempt at a Solution



I don't know whether I dot this, cross product this. I'm lost as where to go from here.
 
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note that the line is parallel to both planes. so it is perpendicular to both planes' normals. If you can find the normal of each planes (which you have), how can you use those 2 vectors to find a vector perpendicular to both?
 
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lanedance said:
note that the line is parallel to both planes. so it is perpendicular to both planes. If you can find the normal of each planes (which you have), how can you use those 2 vectors to find a vector perpendicular to both?

I'm sure you mean both planes normals. :wink:
 
cheers, updated it
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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