Kinematics question concerning the direction of avg acceleration

AI Thread Summary
To find the average acceleration of a car changing its velocity from 25 m/s east to 25 m/s south over 15 seconds, the correct method involves calculating the change in velocity vector. The resultant vector from the initial to final velocity indicates the direction of acceleration. The calculated average acceleration is 2.4 m/s², but the direction is crucial; it is 45 degrees south of west, not south of east. This is because the change in velocity vector points from the initial eastward direction to the final southward direction, resulting in an angle relative to the west. Understanding vector addition and the orientation of the resultant vector is key to determining the correct direction of acceleration.
justrandom94
Messages
2
Reaction score
0
alright so here's a pretty straight forward question asking to find the avg acceleration:

A car with a velocity of 25m/s [E] changes its velocity to 25 m/s in 15s. Calculate
avg acceleration.

So i drew out the vector diagram, found the resultant velocity and solved for the avg acceleration. My answer was right but the direction was wrong. My answer was 2.4 m/s^2 [45 degrees south of east ]
however, the books answer is 2.4 m/s^2 [45 degrees S of W] Can anyone explain to me
why it is south of WEST and not East?
 
Physics news on Phys.org
if the acceleration was all going south and east then the velocity would only increase in the south and east directions
after the cars velocity has changed, what happened to the eastward component of velocity?
 
when i drew it out first i drew out the east ward vector then the south one, and the resultant vector connecting the two allows me to use Pythagorean therom so no components were needed to find the resultant velocity, the east velocity and south velocity are at right angles to one another
 
justrandom94 said:
alright so here's a pretty straight forward question asking to find the avg acceleration:

A car with a velocity of 25m/s [E] changes its velocity to 25 m/s in 15s. Calculate
avg acceleration.

So i drew out the vector diagram, found the resultant velocity and solved for the avg acceleration. My answer was right but the direction was wrong. My answer was 2.4 m/s^2 [45 degrees south of east ]
however, the book's answer is 2.4 m/s^2 [45 degrees S of W] Can anyone explain to me
why it is south of WEST and not East?

You need to find the change in velocity, divided by the elapsed time.

\vec{\Delta v}=\vec{v}_{\text{final}}-\vec{v}_{\text{initial}}

You can also find the change in velocity by asking yourself: what vector must be added to the initial velocity so that the resultant is equal to the final velocity?
\vec{v}_{\text{final}}=\vec{v}_{\text{initial}}+ \vec{\Delta v}​
 
justrandom94 said:
when i drew it out first i drew out the east ward vector then the south one, and the resultant vector connecting the two allows me to use Pythagorean therom so no components were needed to find the resultant velocity, the east velocity and south velocity are at right angles to one another

okay, the vector that points from the initial velocity to the final velcity, it is the one that gives you the change in velocity, what way is that vector facing?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top