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Ion-dipole effects vs. atomic radius

 
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Feb14-12, 01:17 AM   #1
 

Ion-dipole effects vs. atomic radius


When dissolved in water, which of the following ions will form stronger ion-dipole bonds with the water molecules? Li+ or Na+?

Both have roughly the same charge... Na has greater radius, but I don't see why or how that has any bearing on the problem.
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Feb14-12, 02:55 AM   #2
 
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Radius changes distance between charges.
Feb14-12, 03:03 PM   #3
 
Quote by Borek View Post
Radius changes distance between charges.
I'm sorry but could you please elaborate a little more on that?
Radius I guess does decrease the force between the metal ion and each water molecule (due to Coulomb's law), but it turns out that Li+ actually forms more bonds with water. Why is that?
Feb14-12, 04:48 PM   #4
 
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Ion-dipole effects vs. atomic radius


Smaller ion means dipoles are closer to the charge, so the Coulomb force is larger.
Feb14-12, 05:52 PM   #5
 
I believe this has to do with the difference in electronegativity. Lithium has a higher electronegativity.
Feb15-12, 02:27 AM   #6
 
Recognitions:
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Solvation is often treated within a simple model, the Born model, which treats the atom as a charged sphere inside the medium assumed to be continuous and described by its dielectric constant. The model is still used a lot to describe the solvation of proteins even today.
Confer e.g.
http://pchemandyou.blogspot.com/2008...solvation.html
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