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Ion-dipole effects vs. atomic radius |
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| Feb14-12, 01:17 AM | #1 |
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Ion-dipole effects vs. atomic radius
When dissolved in water, which of the following ions will form stronger ion-dipole bonds with the water molecules? Li+ or Na+?
Both have roughly the same charge... Na has greater radius, but I don't see why or how that has any bearing on the problem. |
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| Feb14-12, 02:55 AM | #2 |
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Radius changes distance between charges.
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| Feb14-12, 03:03 PM | #3 |
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Radius I guess does decrease the force between the metal ion and each water molecule (due to Coulomb's law), but it turns out that Li+ actually forms more bonds with water. Why is that? |
| Feb14-12, 04:48 PM | #4 |
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Ion-dipole effects vs. atomic radius
Smaller ion means dipoles are closer to the charge, so the Coulomb force is larger.
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| Feb14-12, 05:52 PM | #5 |
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I believe this has to do with the difference in electronegativity. Lithium has a higher electronegativity.
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| Feb15-12, 02:27 AM | #6 |
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Recognitions:
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Solvation is often treated within a simple model, the Born model, which treats the atom as a charged sphere inside the medium assumed to be continuous and described by its dielectric constant. The model is still used a lot to describe the solvation of proteins even today.
Confer e.g. http://pchemandyou.blogspot.com/2008...solvation.html |
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