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Joint pmf of 2 binomially distributed random variables

by cimmerian
Tags: binomial ditribution, joint pdf
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cimmerian
#1
Mar2-12, 03:36 PM
P: 15
I hope I wrote that correctly but I'm trying to find the joint. I heard it was impossible from someone.

X = A/R
A~BIN(n1, p1)
R~BIN(n2, p2)

I know I shouldn't be using the Jacobian method for Discrete distributions but I have to do it anyway.

Anyone know?
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mathman
#2
Mar2-12, 04:06 PM
Sci Advisor
P: 6,076
The major difficulty arises from the fact that P(R=0) > 0, so you have a non-zero probability of X being infinite.


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