# Newton-Raphson on Matlab

by roam
Tags: matlab, newtonraphson
 P: 884 In MATLAB, I want to use the Newton-Raphson method with absolute tolerance 1e-1, other tolerances zero, and an initial estimate x0 = 4 to find a zero of the function f(x) = tan-1 (x-1) - 0.5 And then repeat the process for a better estimate with absolute tolerance 10-9. So here is my code so far: format long x=4; ind=0; k=1; f=@(x)(atan(x-1)-0.5); fp=@(x)(1/((x - 1)^2 + 1)); N=30; tola=1e-1; tolr=0; tolf=0; while ind == 0 & k <= N, fp_value=feval(fp,x); if fp_value ~= 0, f_value=feval(f,x); if abs(f_value)>tolf, x_new=x - f_value/fp_value; if abs(x_new - x)<= tola + tolr * abs(x), ind=2; end x=x_new; else ind=1; end else ind=3; end k=k+1; end if ind==0, ind=4; end x But we get: x = -2.742845125833007e+211 So why is it that we don't get a single number instead of all 30 iterations? Also when I changed the value of the absolute tolerance to 10^-9, there was no change in the output. Why is that? I'm new to Matlab, so any help is greatly appreciated.

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