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Angular Acceleration of Bicycle Wheels |
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| Jul12-12, 08:38 PM | #1 |
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Angular Acceleration of Bicycle Wheels
1. The problem statement, all variables and given/known data
A wheel has bicycle of diameters 109.0 cm. The bicyclist accelerates from rest with constant acceleration to 16.3 km/hr in 16.5 s. What is the angular acceleration of the wheels? 2. Relevant equations w=v/r alpha= w/t 3. The attempt at a solution I think I'm doing it right, however, I was hoping someone might check my logic First I convert diameter 109 cm to radius .545 m and 16.3 km/hr to 4.527 m/s. I solve for w using linear speed divided by r = 4.527/.545 = 8.3078 rad/s Solve for alpha using a = (wf-wi)/t = (8.3078-0)/16.5 s = .5035 rad/s^2 |
| Jul12-12, 08:55 PM | #2 |
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Mentor
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Your method seems good to me
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