
#1
Nov2612, 11:26 AM

P: 3

A 13 kg box is placed at the top of a 4.5 m long, ramp inclined at an angle of 41 degrees (with the horizon). However, the ramp is covered with sand so the coefficient of friction is 0.19. How much time does it take the box to reach the bottom of the ramp?
Fgx=Fg sin=mg sin. 13kg (9.8 N/kg)=127N 127N Sin 41= 83N Acceleration=83N/13kg=6.4m/s 4.5m=1/2 (6.4m/s)t^2 4.5m=3.2m/s t^2 t=1.19s Im just confused as where the coefficient of friction comes into play, and how to solve it. 



#2
Nov2612, 11:42 AM

P: 265

As the box travels down the ramp, there is a frictional force on it and well as the gravitational force.
Draw the freebody diagram and work out the net force on the box down the ramp. 


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