Why is Vi - Vf used to calculate voltage in circuits?

AI Thread Summary
The discussion centers on the calculation of voltage across circuit elements using the formula Vi - Vf, which some find contradictory. The reasoning suggests that this approach measures the potential energy changes of circuit elements rather than the current itself, leading to a negative relationship between the two. Participants express frustration over a lack of clear explanations in textbooks, prompting a search for better resources. A reference to Kirchhoff's voltage law is made, indicating its relevance to understanding these calculations. Overall, clarity in circuit analysis and educational resources is sought to better grasp these concepts.
Miike012
Messages
1,009
Reaction score
0
My question is why did they choose to calculate the voltage across a circuit element as vi - vf because it seems contradictory.
More detail is in the document.

Someone please answer because this has been bothering me.
THank you.
 

Attachments

  • VOLT VOLT.jpg
    VOLT VOLT.jpg
    20.3 KB · Views: 396
Engineering news on Phys.org
My guess is that instead of calculating the potential energy drops/gains of current they are calculating the potential energy drops/gains of the circuit elements which is the negative of the potential energy drops/gains of current. It's just frustrating because the book doesn't explain why they are doing what they are doing. Are there any first semester circuits books that give explanations? The book I am reading from is
https://www.amazon.com/dp/0470633220/?tag=pfamazon01-20
 
If you use Vi-Vf then you would change the signs. Vi -Vf = -(Vf-Vi). When you calculated it you used Vf-Vi.

BTW, Vr1 + Vr2 - M = 0.

When you start at the bottom, you first go into the - side of the battery, and then into the + side of two resistors.

Read the wikipedia page on kirchhoffs voltage law.
 
While I was rolling out a shielded cable, a though came to my mind - what happens to the current flow in the cable if there came a short between the wire and the shield in both ends of the cable? For simplicity, lets assume a 1-wire copper wire wrapped in an aluminum shield. The wire and the shield has the same cross section area. There are insulating material between them, and in both ends there is a short between them. My first thought, the total resistance of the cable would be reduced...
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...
Back
Top