Exponential distribution, memory

AI Thread Summary
The exponential distribution is unique in being memoryless, meaning that the probability of an event occurring in the future is independent of past events. This property is mathematically defined as P(X > s + t | X > t) = P(X > s), which does not hold for distributions like the normal distribution that can take on negative values. In contrast, while random selections from both distributions may appear independent, the exponential distribution's memoryless characteristic is a specific mathematical property. Other distributions, including the normal distribution, do not satisfy this condition, which is why they are not considered memoryless. Understanding this distinction clarifies the unique nature of the exponential distribution.
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I am told that an exponential distribution is memoryless. But why aren't other distributions, such as the normal distribution, also memoryless? If I pick a random number from an exponential distribution, it is not effected by previously chosen random numbers. But isn't that also the case for a normal distribution, for example?

What do I misunderstand?

Thank you
 
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I think when people say the exponential distribution is memoryless, they mean that, for any exponentially distributed random variable X, the distribution of X-x conditional on the event \{X\geq x\} is the same as the distribution of X.

It's easy to check that that the normal distribution (or, in fact, anything that can take on negative values) can't satisfy the above property.
 
The memory less notion refers to the fact that for any positive numbers s and t

<br /> P(X &gt; s + t | X &gt; t) = P(X &gt; s)<br />

It can be shown that this property gives the exponential distribution as the unique continuous distribution with the property.
 
Thank you
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...
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