
#1
Oct705, 12:57 PM

P: 3

I've already determined the first part of the question, which is regarding the buoyant force. An object weights 5N and displaces 3.5 N of water when placed in the beaker. The buoyant force is = to the displaced water which is 3.5N. Now, here's where I'm stuck. The volume doubles, and weight stays the same. What is the buoyant force? My guess is that since the volume is doubling, the amount displaced will double so it will be 7N and the object will float because the amount displaced is greater than the weight. Is that accurate?




#2
Oct705, 01:56 PM

HW Helper
P: 879

Not accurate, I'm afraid.
The volume of the object may double but it will only displace double the original volume of water if it it completely immersed. If you think about it ... The downward force, the weight of the object, is 5N and if the upwards force, the buoyant force, is 7N, then the object is going to accelerate upwards! When the volume doubles, try to figure out if the object floats or will it be completely immersed. 



#3
Oct705, 02:10 PM

HW Helper
P: 661





#4
Oct705, 02:17 PM

P: 3

Buoyant Force and Volume
Then the object would float then because the deeper the object is immersed, the greated the buoyant focce and once the weight of the disperased water is equal to the weight of the object, it will float. Since the volume is doubled, the bouyant force will never really double because once it equals the weight it will float. Density plays a role because the more dense an item is, the less it has to be immersed in order to displace the amount of water to float?




#5
Oct705, 02:52 PM

HW Helper
P: 661





#6
Oct705, 03:30 PM

P: 3

Thank You All For Your Help! :)



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