What Are the Different Coordinate Systems Used in Calculus?

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SUMMARY

This discussion focuses on the conversion of expressions between different coordinate systems in calculus, specifically polar, cylindrical, and Cartesian coordinates. Users provided methods for rewriting second derivatives in polar coordinates using the relationships x = rcos(θ) and y = rsin(θ). Additionally, the discussion included expressing the surface z = rcos³(φ) in Cartesian coordinates and solving for p, φ, and θ in terms of x, y, and z using cylindrical coordinates. The conversation highlights the challenges faced by users in understanding these coordinate transformations.

PREREQUISITES
  • Understanding of polar coordinates and their relationships to Cartesian coordinates
  • Familiarity with cylindrical coordinates and their geometric interpretations
  • Basic knowledge of calculus, specifically derivatives and second derivatives
  • Ability to manipulate mathematical expressions and coordinate transformations
NEXT STEPS
  • Learn how to convert between polar and Cartesian coordinates in detail
  • Study the geometric interpretations of cylindrical coordinates
  • Explore the application of the chain rule in multivariable calculus
  • Investigate the use of Jacobians in coordinate transformations
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Students and educators in mathematics, particularly those studying calculus and coordinate systems, as well as anyone seeking to improve their understanding of multivariable calculus concepts.

JasonJo
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1) Rewrite the following expression in polar coordinates:
(second derivative of z with respect to x) + (second derivative of z with respect to y)

where x=rcos(theta)
y = rsin(theta)

i had first derivative of z with respect to x = (dz/dx)(dx/dr) + (dz/dx)(dx/d(theta))

same concept for y

and then i just took the derivative of my dz/dz and dz/dy variables again

2) describe this surface in cylindrical coordinates
z = rcos3(phi)

express in cartesian coordinates

i really do not get cartesian coordinates

can anyone show me the generic method?

3) x = psin(phi)cos(theta)
y = psin(phi)sin(theta)
z = pcos(phi)

near which points of R^3 can we solve for: p phi and theta in terms of x, y and z, describe the geometry behind your answer.

again, i am really really weak in coordinate systems.

any help is appreciated, thanks guys
 
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what does z = in #1

x = p sin phi cos theta

y =p sin phi sin theta

z = p cos phi
 

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