How does the gravitational force between two objects change with distance?

  • Thread starter Thread starter elle
  • Start date Start date
  • Tags Tags
    Gravitational
AI Thread Summary
The discussion centers on understanding how gravitational force changes with distance using the formula for gravitational attraction. Participants clarify that "r" represents the distance between the centers of two objects, which is sometimes denoted as "d" in diagrams. It's noted that for the problem at hand, the masses of the objects and the gravitational constant (G) can be simplified or canceled out, making the calculations easier. The main challenge expressed is the confusion around the formula and the variables involved, particularly for someone new to physics. Overall, the focus is on applying the gravitational formula correctly to analyze the effects of distance on gravitational force.
elle
Messages
91
Reaction score
0
Last edited by a moderator:
Physics news on Phys.org
You know what r is in both cases so just use the formula to express F and F' for both cases and compare the two results.
 
I still don't understand...where does R come into the formula?? :rolleyes:
 
r is the distance between the center of the Earth and the object in question. That is the symbol people usually use but I just noticed the picture you showed uses "d" to represent that distance so r is the same as your d.
 
Ok please bear with me if I sound dumb...never taken physics before so I'm finding it realli difficult :cry:
So do I have to find m1 and m2? And for G I've been given an approximation for it, and I don't know if I'm suppose to use it :confused:
 
Assuming that neither the mass of the plane nor of the Earth change then they both cancel out - along with G! They made it really convenient for you. :)
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top