Calculating Final Speeds of Pucks A and B After Collision

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The discussion revolves around calculating the final speeds of two pucks after a collision on an air-hockey table. Puck A, with a mass of 0.024 kg and an initial velocity of +5.5 m/s, collides with stationary puck B, which has a mass of 0.054 kg. After the collision, puck A moves at an angle of 65 degrees to the x-axis, while puck B moves at 37 degrees. The user expresses difficulty in applying the conservation of momentum and energy formulas due to the presence of two unknowns. Assistance is sought to break down the components and determine the final speeds of both pucks.
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The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.024 kg and is moving along the x-axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.054 kg and is initially at rest. After the collision, the two pucks fly apart with the angles 65 for a to the x axis, and37 for b to the x axis. A going up, B down.


Find the final speed of
(a) puck A and
(b) puck B.
m/s

I tired and tried and it dod not work out. the formula i am using has the 2 unknowns in it so it is impossible to solve. Breaking up into components i don't know how, what would the Vi of the speeds be and in what direction. This HW is due tomorrow and this is the first time i am stuck like this. Please help those who know how!

Thanks
 
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you need to use the laws of conservation of momenteum and energy

m1v1i + m2v2i = m1v1f + m2v2f

and

1/2m1v1i^2 + 1/2m2v2i^2 = 1/2m1v1f^2 + 1/2m2v2f^2
 
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