- #1
Civil_Disobedient
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Homework Statement
A person runs at a constant speed of 4.0 m/s to catch a stationary bus. When she is 6.0m behind it (t=0s), the bus leaves, accelerating with a (constant) acceleration of 1.2 m/s^2. How long does it take her to catch up to the bus?
Homework Equations
X = Xo + Vot + 0.5at^2
The Attempt at a Solution
Variables for the person:
Vo = 4
Xo = -6
Variables for the bus:
Vo = 0
Xo = 0
a = 1.2
Equation for the person:
X = Xo + Vot
X = -6+4t
Equation for the bus:
X = 0.5at^2
X = 0.5(1.2)t^2
X = 0.6t^2
Setting the two equations equal to each other, I got:
-6 + 4t = 0.6t
-3.4t = -6
t = 5.67s
Not sure what to do from here or if I even did everything correctly up to this point. Thanks for your help.