A 6kg box is placed on a 32degree frictionless ramp. Find accel. of the box.

In summary, the conversation discusses the use of components in solving a problem involving rotation of axes. The component of the weight vector down the ramp is the force that accelerates the box, and it is easier to use components along the ramp and normal rather than horizontal and vertical components.
  • #1
Kaxa2000
71
0
I have the solution to the problem but I don't get the part how you rotate the axes and then solve from there.

For example in the x direction
Fx = max

+mg sin32 = max

Fx = Force in x direction
ax = acceleration in the x direction

Can someone explain this?
 
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  • #2
You're taking the component of the weight vector down the ramp. That is the force that accelerates the box.
 
  • #3
Welcome to PF!

Hi Kaxa2000! Welcome to PF! :smile:
Kurdt said:
You're taking the component of the weight vector down the ramp. That is the force that accelerates the box.

I'll just add that you shouldn't think of it as a rotation …

everything stays as it is, and you simply choose to take components in whatever direction is most conveniento:)

for example, you could use horizontal and vertical components …

but that would give you two equations :redface:, while choosing along-the-ramp and normal gives you only one relevant equation, which is much easier! :wink:
 

Related to A 6kg box is placed on a 32degree frictionless ramp. Find accel. of the box.

1. What is the formula for calculating acceleration on a ramp?

The formula for calculating acceleration on a ramp is a = sin(θ) * g, where θ is the angle of the ramp and g is the gravitational acceleration (9.8 m/s²).

2. How do you determine the angle of the ramp?

The angle of the ramp can be determined using the formula θ = tan⁻¹ (h/l), where h is the height of the ramp and l is the length of the ramp.

3. What is the weight of the 6kg box?

The weight of the 6kg box can be calculated using the formula F = m * g, where m is the mass of the box and g is the gravitational acceleration (9.8 m/s²). In this case, the weight of the box would be 6kg * 9.8 m/s² = 58.8 N.

4. Why is friction not taken into account in this problem?

In this problem, it is stated that the ramp is frictionless, which means there is no force acting against the motion of the box. Therefore, friction does not need to be considered in the calculation of the box's acceleration.

5. How does the mass of the box affect its acceleration?

According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that the greater the mass, the lower the acceleration will be, assuming that the force is constant. In this problem, the mass of the box is 6kg, so it will have a lower acceleration compared to a lighter box with the same force acting on it.

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