- #1
PG222
- 1
- 0
Homework Statement
A bushranger hanging out of a hotel window wishes to drop vertically onto a horse galloping under the window. The constant speed of the horse is 14.0 m/s, and the distance from the window to the level of the saddle is 2.50 m.
(a) What must be the horizontal distance between the saddle and window sill when the bushranger makes his move?
(b) For what time interval is he in the air?
Homework Equations
I'm not too sure of what equations I was meant to use but I tried this:
X=-2.5
X=0.5(-9.8)t^2
D=Ut
The Attempt at a Solution
Using the above equations I worked t out to be 0.714 seconds
And for the horizontal distance I ended up with 10 meters
Last edited: