A neutral metal rod in a uniform magnetic field

In summary, a neutral metal rod of length 0.35 m slides horizontally at a constant speed of 9 m/s on frictionless insulating rails through a region of uniform magnetic field of magnitude 0.6 tesla. After the initial transient, the net force on a mobile electron inside the rod is 0 N. The magnitude of the electric force on a mobile electron inside the rod is 8.64E-19 N, while the magnetic force is also 8.64E-19 N. The potential difference across the rod is 1.89 V. The discrepancy in the electric force calculation is due to the use of absolute value instead of the negative value.
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Homework Statement



A neutral metal rod of length 0.35 m slides horizontally at a constant speed of 9 m/s on frictionless insulating rails through a region of uniform magnetic field of magnitude 0.6 tesla, directed into the page as shown in the diagram. Before answering the following questions, draw a diagram showing the polarization of the rod, and the direction of the Coulomb electric field inside the rod.

(A) After the initial transient, what is the magnitude of the net force on a mobile electron inside the rod?

(B) What is the magnitude of the electric force on a mobile electron inside the rod?

(C) What is the magnitude of the magnetic force on a mobile electron inside the rod?

(D) What is the magnitude of the potential difference across the rod?




Homework Equations


Fmag + F(e) = F
Fmag = qBV
dV = EdL

The Attempt at a Solution



(A) After the initial transient, what is the magnitude of the net force on a mobile electron inside the rod?
|Fnet|= 0 N (correct)
(B) What is the magnitude of the electric force on a mobile electron inside the rod?
|Fe|= 8.64E-19 N (incorrect)
(C) What is the magnitude of the magnetic force on a mobile electron inside the rod?
|Fmag|= 8.64E-19 N (correct)
(D) What is the magnitude of the potential difference across the rod?
|dV|= 1.89 V (correct)



Why am I getting the electric force wrong (all the others are correct)? If:


Fnet = 0, then:

Fmag + F(E) = 0, therefore:

F(E) = -Fmag, and when:

Fmag = 8.64E-19 N, then

F(E) = -8.64E-19 N, right?

How come it's not?
 

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  • #2
Wait a minute, I got it; the stupid thing wants to the ABSOLUTE VALUE.
 

Related to A neutral metal rod in a uniform magnetic field

1. What is a neutral metal rod?

A neutral metal rod is a cylindrical object made of a conductive material, such as copper or aluminum, that has an equal number of positive and negative charges. This means that it has no overall charge and is electrically neutral.

2. What is a uniform magnetic field?

A uniform magnetic field is a type of magnetic field where the strength and direction of the magnetic field is consistent throughout the entire region. This means that the magnetic field lines are parallel and evenly spaced.

3. How does a neutral metal rod interact with a uniform magnetic field?

A neutral metal rod placed in a uniform magnetic field will experience a force perpendicular to both the direction of the magnetic field and the direction of the current flowing through the rod. This is known as the Lorentz force and is responsible for the motion of the rod.

4. What happens if the neutral metal rod is not in a uniform magnetic field?

If the neutral metal rod is not in a uniform magnetic field, it will experience a non-uniform force due to the varying strength and direction of the magnetic field. This can cause the rod to rotate or move in a curved path.

5. How can a neutral metal rod be used in practical applications?

A neutral metal rod in a uniform magnetic field is commonly used in devices such as electric motors and generators. By using the Lorentz force, the rod can be used to convert electrical energy into mechanical energy or vice versa.

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