- #1
saltyload
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The plane is inclined at a 30 degree angle. The coefficient of kinetic friction between the mass and the plane is 0.1. The mass is 100kg. If the mass is moving up the inclined plane at a velocity of 2m/s, what tension should be applied to the rope in order to make the mass reverse directions in exactly 1 sec?
mgsin(theta)
mgcos(theta)
Fk = coefficient x mgcos(theta)
V = Vi + at
V = Vi + at a = 4m/s^2
Equation I used to solve:
ma = mgsin(theta) - T - Fk(theta)
My answer was 187N, actual answer is 387N. No idea how I can manipulate the equation to get 200N more.
mgsin(theta)
mgcos(theta)
Fk = coefficient x mgcos(theta)
V = Vi + at
V = Vi + at a = 4m/s^2
Equation I used to solve:
ma = mgsin(theta) - T - Fk(theta)
My answer was 187N, actual answer is 387N. No idea how I can manipulate the equation to get 200N more.