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mikefitz
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An aluminum cylinder weighs 1.01 N. When this same cylinder is completely submerged in alcohol, the volume of the displaced alcohol is 3.88 × 10-5 m3. The apparent weight of the cylinder when completely submerged is 0.778 N. What is the specific gravity of the alcohol?
m=W/g
m(cylinder)=.10296 kg
p=m/V
.10296kg/3.88*10^5 => 2653.608kg/m^3 (avg density)
SG= 2653.608/1000=> 2.65
What did I do wrong? Thanks
m=W/g
m(cylinder)=.10296 kg
p=m/V
.10296kg/3.88*10^5 => 2653.608kg/m^3 (avg density)
SG= 2653.608/1000=> 2.65
What did I do wrong? Thanks