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MajesticPenguin
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Homework Statement
An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of 4.5*10^4 kg, and the force causes its speed to change from 7100m/s to 5500m/s.
(a) What is the work done by the force?
(b) If the asteroid slows down over a distance of 1.8*10^6m, Determine the magnitude of the force.
Homework Equations
W=F*cos(theta)*s
F=ma
instantaneous acceleration = delta(v)/delta(t) as limit of t approaches 0.
W=KEf-KEo= 1/2MVf^2 - 1/2MVo^2
The Attempt at a Solution
First, I looked for the instantaneous acceleration created by the force by subtracting 7100m/s - 5500m/s
a= 16,000 m/s. This means the force slowed down the asteroid by 1.6*10^4 m/s.
I multiply 45,000 kg by 16,000 m/s to calculate the force.
F= 7.2*10^8 N
I plug this into my work equation:
W=7.2*10^8*cos(180)*s
that's where I'm stuck because I'm not sure what my displacement is.
I tried the last equation and found initial Kinetic energy as Ke=1/2mv^2
so: 1/2(4.5*10^4kg)(7100m/s)^2
= 1.13*10^12
final kinetic is initial kinetic + work
1.13*10^12 + Fcos(theta)s
I feel like I may be over-complicating this question. I feel like I'm close but I'm missing something obvious. Help appreciated!