- #1
StevenJacobs990
- 16
- 0
Is this a legitimate equation?
θ'' = − g⁄R sin θ
Source: ftp://www.myphysicslab.com/pendulum1.html
ftp://www.myphysicslab.com/images/pendulum_2.gif
The pendulum is modeled as a point mass at the end of a massless rod. We define the following variables:
−R m g sin θ = m R2 α
which simplifies to
θ'' = − g⁄R sin θ
θ'' = − g⁄R sin θ
Source: ftp://www.myphysicslab.com/pendulum1.html
ftp://www.myphysicslab.com/images/pendulum_2.gif
The pendulum is modeled as a point mass at the end of a massless rod. We define the following variables:
- θ = angle of pendulum (0=vertical)
- R = length of rod
- T = tension in rod
- m = mass of pendulum
- g = gravitational constant
- τ = net torque
- I = rotational inertia
- α = θ''= angular acceleration
−R m g sin θ = m R2 α
which simplifies to
θ'' = − g⁄R sin θ
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