Arhenius equation solving for K1/T2

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The discussion focuses on solving the Arrhenius equation for K2 or T2, using the formula ln(K1/K2) = Ea/R(1/T1) - (1/T2). The user struggles to isolate K2 and T2, leading to incorrect answers compared to the professor's expected result of 6.07. Participants suggest using simple algebra to manipulate the equation and provide guidance on isolating the variables. The user is encouraged to show their work for better assistance. The conversation emphasizes the importance of understanding the algebraic steps involved in solving the equation.
lazybone
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Hey guys its my first time in this forum and I need help with my chemistry. I guess its kind if basic chem. Basically its a question to solve for K2 or T2. Like I'm not sure how to isolate the k or T.


Homework Statement




Homework Equations



ln(K1/K2)=Ea/R(1/T1)-(1/T2)

Ln(23/x)=139J/8.314J(1/750)-(1/800)


The Attempt at a Solution



I keep getting a different answer than the real one . My professor said it is 6.07. Please help I'm not sure how to isolate the K2. And what happens if I need to find T2. Thanks
 
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Use simple Algebra to solve this. Show some work on how you tried to isolate it, and I will then guide you on how to figure it out.
 
lazybone said:

Homework Equations



ln(K1/K2)=Ea/R(1/T1)-(1/T2)

Ln(23/x)=139J/8.314J(1/750)-(1/800)

The equation is: ln(K1/K2)=Ea/R[(1/T1)-(1/T2)]
 

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