How Does Light Intensity and Frequency Affect Photoelectron Emission?

In summary, when low intensity light is shone on a metal, it does not release any photoelectrons. If the light is made brighter, the number of photoelectrons emitted will increase. However, if the frequency of the light is gradually increased, then photoelectrons will be emitted.
  • #1
chef99
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4

Homework Statement



Use Max Planck’s quantum theory to explain the following behavior of photoelectrons.

a) Low-intensity light does not release any photoelectrons. What will happen if the light is made brighter? Explain your reasoning

b) Low-intensity light releases photoelectrons. What will happen if the light is made brighter? Explain your reasoning.


c) Low-intensity light does not release any photoelectrons. What will happen if the frequency of the light is gradually increased? Explain your reasoning.2. Homework Equations
n/a

The Attempt at a Solution

a)[/B]
For a metal to emit photoelectrons, the frequency of the light must be above the threshold frequency of the metal. Since this light doesn’t emit any photoelectrons, its frequency must be below the metal’s threshold frequency. Therefore, making the light brighter will still not produce any photoelectrons from the metal.
b)
Since this low-intensity light emits photoelectrons, its frequency is above the threshold frequency. If the brightness is increased, the intensity is also increased, meaning the number of photoelectrons emitted will increase.c)
If the frequency is increased past the threshold frequency, then the light will begin to emit photoelectrons.I feel I might be mixing something up here, as my answers to b and c seem very similar. I don't know if they are supposed to. Any help here would be great.
 
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  • #2
chef99 said:
b) Low-intensity light releases photoelectrons. What will happen if the light is made brighter? Explain your reasoning.
<snip>
Since this low-intensity light emits photoelectrons, its frequency is above the threshold frequency. If the brightness is increased, the intensity is also increased, meaning the number of photoelectrons emitted will increase.

Are you thinking that making the light brighter means increasing the number of photons or the energy of the photons?
 
  • #3
Fewmet said:
Are you thinking that making the light brighter means increasing the number of photons or the energy of the photons?

Yes, but that is what I am confused about. Initially, I thought the brightness doesn't have an effect on frequency, which I know does have an effect on the energy of photons. Everything I have been able to find has said that increasing the brightness means increasing the intensity, which I believe would also increase the number of photons emitted. However, this is just what I've been able to research, as I initially didn't know the answer.
From what I understand, increasing frequency increasing the energy of the photons, and increasing the intensity increases the number of photons. Is that correct?
 
  • #4
I think the textbook question is a little ambiguous, but I might be overlooking a convention I have not noticed before.

The text I usually work from discusses this in the context of Einstein's experiments, and that description specifies that he increased the intensity at a constant frequency. Unless your text's discussion indicates otherwise, the way the question is structured leaves me confident the intent is that the light is made brighter while keeping the frequency constant.

Does that resolve your question?
 
  • #5
Fewmet said:
I think the textbook question is a little ambiguous, but I might be overlooking a convention I have not noticed before.

The text I usually work from discusses this in the context of Einstein's experiments, and that description specifies that he increased the intensity at a constant frequency. Unless your text's discussion indicates otherwise, the way the question is structured leaves me confident the intent is that the light is made brighter while keeping the frequency constant.

Does that resolve your question?

Yes, thank you for your help.
 
  • #6
chef99 said:
I feel I might be mixing something up here, as my answers to b and c seem very similar. I don't know if they are supposed to. Any help here would be great.

No, you're not mixing things up. However, you can be a bit more explicit in your description for (c). You could say that as the frequency increases, at first there is no photoelectrons emitted until it reaches the threshold frequency. Beyond this value, photoelectrons are detected as frequency keeps on increasing.

You do not have to worry about intensity, etc. for this question since it doesn't say what happens to the intensity. All it cares about, and all you should care about, is to say what you can say with the given information. So you do not have to describe if you detect more or less photoelectrons. The only thing you can say is if you detect or do not detect photoelectrons.

Zz.
 
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What is the behavior of photoelectrons?

The behavior of photoelectrons refers to how they interact with light and other molecules. When light shines on a metal surface, it can cause some of the electrons in the metal to be released. These released electrons are called photoelectrons.

What is the photoelectric effect?

The photoelectric effect is the phenomenon where electrons are emitted from a metal surface when light of a certain frequency shines on it. This effect was first observed by Heinrich Hertz in 1887 and was later explained by Albert Einstein in 1905.

How does the intensity of light affect photoelectrons?

The intensity of light does not affect the behavior of photoelectrons. However, the number of photoelectrons emitted is directly proportional to the intensity of the incident light. This means that as the intensity of light increases, the number of photoelectrons emitted also increases.

What is the threshold frequency in the photoelectric effect?

The threshold frequency is the minimum frequency of light required to release photoelectrons from a metal surface. If the frequency of light is below the threshold frequency, no photoelectrons will be emitted regardless of the intensity of the light.

How does the work function of a metal affect the behavior of photoelectrons?

The work function of a metal is the minimum amount of energy required to remove an electron from the surface of the metal. The higher the work function of a metal, the more difficult it is to release photoelectrons. This means that metals with higher work functions will require higher frequencies of light to release photoelectrons compared to metals with lower work functions.

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