- #1
J.J.T.
- 17
- 6
I was given the equation of a polynomial told to find the derivative. easy enough.
Then asked to give the equation of the tangent line which I've only learned how to get in the form of the question: "find the equation of the tangent line at x="
They gave me the equation of a line parallel to the tangent.
Typically as we've seen these problems thus far its fairly straightforward derive equation for slope of tangent plug x into the original equation to find the y value and typically put in point-slope form. Alternatively i suppose you could find the y-intercept and put in y=mx+b form but,
How in the heck do you find either the y intercept of the tangent line or the x/y points to do that given only the equation of a parallel line?
Then asked to give the equation of the tangent line which I've only learned how to get in the form of the question: "find the equation of the tangent line at x="
They gave me the equation of a line parallel to the tangent.
Typically as we've seen these problems thus far its fairly straightforward derive equation for slope of tangent plug x into the original equation to find the y value and typically put in point-slope form. Alternatively i suppose you could find the y-intercept and put in y=mx+b form but,
How in the heck do you find either the y intercept of the tangent line or the x/y points to do that given only the equation of a parallel line?
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