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Im having a little trouble finding the orbital period of Earth using:
[tex]t_{years}=2\pi\sqrt{\frac{a^3}{GM}}[/tex]
"M" being the mass of the central body, obviously the sun, at 2 x 10^30 kg
"a" being the semi-major distance in Au = 1
So,
[tex]\approx[/tex]
[tex]t_{years}=6.28\sqrt{\frac{1}{6.673*2}}*\sqrt{\frac{1}{10^{-11}*10^{30}}[/tex]
[tex]t_{years}=6.28\sqrt{.0749}*\sqrt{10^{-19}}[/tex]
[tex]t_{years}=6.28*.2736*(3.16*10^{-10})[/tex]
[tex]t_{years}=5.428*10^{-10}[/tex]
[tex]5.428*10^{-10}\neq1year[/tex]
I know I'm doing something terribly wrong, any help appreciated
One other question, the gravitational constant is in Newton/seconds right?
[tex]t_{years}=2\pi\sqrt{\frac{a^3}{GM}}[/tex]
"M" being the mass of the central body, obviously the sun, at 2 x 10^30 kg
"a" being the semi-major distance in Au = 1
So,
[tex]\approx[/tex]
[tex]t_{years}=6.28\sqrt{\frac{1}{6.673*2}}*\sqrt{\frac{1}{10^{-11}*10^{30}}[/tex]
[tex]t_{years}=6.28\sqrt{.0749}*\sqrt{10^{-19}}[/tex]
[tex]t_{years}=6.28*.2736*(3.16*10^{-10})[/tex]
[tex]t_{years}=5.428*10^{-10}[/tex]
[tex]5.428*10^{-10}\neq1year[/tex]
I know I'm doing something terribly wrong, any help appreciated
One other question, the gravitational constant is in Newton/seconds right?
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