- #1
jk22
- 729
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I'm confused, Is the value of ##(dr)^2##
$$dx^2+dy^2+dz^2$$
Or $$\frac{(xdx+ydy+zdz)^2}{x^2+y^2+z^2}$$
?
$$dx^2+dy^2+dz^2$$
Or $$\frac{(xdx+ydy+zdz)^2}{x^2+y^2+z^2}$$
?
The formula for calculating (dr)^2 is (r^2)(d^2), where r is the radius and d is the diameter of a circle.
If you only know the circumference of a circle, you can use the formula (C/π)^2, where C is the circumference, to calculate (dr)^2.
Yes, (dr)^2 can be used to find the area of a circle. The formula for calculating the area of a circle is π(r^2), which is equivalent to (dr)^2.
(dr)^2 is commonly used in geometry and math to calculate the area of circles. It is also used in fields such as engineering and physics to calculate the moment of inertia, which is a measure of an object's resistance to rotational motion.
(dr)^2 can be used to solve a variety of practical problems, such as calculating the amount of paint needed to cover a circular wall or determining the size of a circular garden. It can also be used to calculate the rotational energy of an object or the speed of a rotating object.