Calculating electric flux when given a charge (Gauss)

Your answer should have 3 sig figs (one decimal place), since that's the precision given in the problem. Try entering 580.8 and see if that works.Are you confusing decimal places and sig figs? If you entered 580.790, you're supplying an answer with 6 sig figs, and that's why it's getting marked wrong. Your answer should have 3 sig figs (one decimal place), since that's the precision given in the problem. Try entering 580.8 and see if that works.I did and it did. Thanks guys I guess it was just a sig fig issue. Thanks for the help.
  • #1
Will12

Homework Statement


A charge Q=5.14 nC
is located at the center is located at the center of a Gaussian sphere of radius R=10.0 cm
. The sphere lies within a uniform upward electric field E=2100 NC
The net outward electric flux through the sphere is What?


Second problem (bonus round!)
A closed Gaussain cube of side length d=10.0cm contains two charges q1=-14uc q2=28uc placed at different locations within the cube (never given a specific placement) what it the net outward flux?

Homework Equations


ξοΦ=qenc
E=q/4πξοr^2 (maybe?)

The Attempt at a Solution



I've tried solving both of these problems but keep getting them wrong and don't know what I'm doing wrong
Problem one
Φ=5.14E-9 C/ξο
Then since the other flux makes a net zero it shouldn't come into play right? or do I need to use the electrostatic force equation and that's also my flux?

Problem two.
I've tried gauss' law after finding the net enclosed charge but that's been wrong every time, I don't even know what equation to start this with, do I need to find the electro static force for each charge first and then add them together so they each cancel in part then do the equation with
ξο∫E*dA?

Thanks for any help you can give me
 
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  • #2
Will12 said:
Problem one
Φ=5.14E-9 C/ξο
Then since the other flux makes a net zero it shouldn't come into play right?
Your answer is correct, unless this problem is not in vacuum such that ##\epsilon## is different.
Will12 said:
Problem two.
I've tried gauss' law after finding the net enclosed charge but that's been wrong every time, I don't even know what equation to start this with, do I need to find the electro static force for each charge first and then add them together so they each cancel in part then do the equation with
This uses the same method as problem 1. Who/What is telling you that this is wrong?
 
  • #3
NFuller said:
Your answer is correct, unless this problem is not in vacuum such that ##\epsilon## is different.

This uses the same method as problem 1. Who/What is telling you that this is wrong?
Orion Personalized practice marks it wrong every time, maybe its a rounding tolerance issue or something else. Ill have to play with it a little more I guess
 
  • #4
Will12 said:
Orion Personalized practice marks it wrong every time, maybe its a rounding tolerance issue or something else.
There must be something wrong with how you are entering the answer. I know some of these programs have a funny way of entering numbers in scientific notation. Try to check that in the help section on Orion.
 
  • #5
Will12 said:
Orion Personalized practice marks it wrong every time, maybe its a rounding tolerance issue or something else. Ill have to play with it a little more I guess
Is a numerical answer expected? What are the units? What did you use for ##\ \varepsilon_0\ ##?
 
  • #6
SammyS said:
Is a numerical answer expected? What are the units? What did you use for ##\ \varepsilon_0\ ##?
8.85E-12 is the value it gives in the book. units vary across problems but its always nc E-9 or uc E-6.
 
  • #7
Will12 said:
8.85E-12 is the value it gives in the book. units vary across problems but its always nc E-9 or uc E-6.
What are the Units for electric flux ?
 
  • #8
SammyS said:
What are the Units for electric flux ?
Newtons*Meter^2/Coulombs
 
  • #9
Will12 said:
Newtons*Meter^2/Coulombs
Correct.

Did you include these in your answer, or were they provided by Orion Personalized practice ?
 
  • #10
SammyS said:
Correct.

Did you include these in your answer, or were they provided by Orion Personalized practice ?
They are provided. Also I've just learned that I can turn on them giving the correct answer after problem completion and they give it in 12345.123456789 format, and don't list a tolerance for rounding anywhere, but have been accepting rounding to one decimal in other portions of the program, In fact I was able to complete the entire cilindrical semitry portion of the program without a single wrong answer using the same online calculator with the same value of Eo and rounding to one decimal place so I don't know what's going wrong
 
  • #11
Will12 said:
They are provided. Also I've just learned that I can turn on them giving the correct answer after problem completion and they give it in 12345.123456789 format, and don't list a tolerance for rounding anywhere, but have been accepting rounding to one decimal in other portions of the program, In fact I was able to complete the entire cilindrical semitry portion of the program without a single wrong answer using the same online calculator with the same value of Eo and rounding to one decimal place so I don't know what's going wrong
What is the numerical answer that you are entering? How many significant digits should it have ?
 
  • #12
SammyS said:
What is the numerical answer that you are entering? How many significant digits should it have ?
For the problem listed above my answer was 580.790 But it doesn't say how may significant figures it wants, or gives a rounding tolerance.
 
  • #13
Will12 said:
For the problem listed above my answer was 580.790 But it doesn't say how may significant figures it wants, or gives a rounding tolerance.
Have you not studied significant figures in your course ?
 
  • #14
SammyS said:
Have you not studied significant figures in your course ?
We have but previously have been instructed regardless of significant figures given by the problem to give three, or one, dependent on which system we were using. Because each system last semester was programed slightly differently and would reject your answers if you were outside of their parameters.
 
  • #15
Will12 said:
For the problem listed above my answer was 580.790 But it doesn't say how may significant figures it wants, or gives a rounding tolerance.
Are you confusing decimal places and sig figs? If you entered 580.790, you're supplying an answer with 6 sig figs, and that's why it's getting marked wrong.
 

1. What is electric flux and why is it important in Gauss's Law?

Electric flux is a measure of the electric field passing through a given surface. It is important in Gauss's Law because it allows us to calculate the net electric charge within a closed surface by measuring the electric flux through that surface.

2. How is electric flux calculated?

Electric flux is calculated by taking the dot product of the electric field and the surface area vector. This can be represented mathematically as Φ = E * A * cos(θ), where Φ is electric flux, E is electric field, A is surface area, and θ is the angle between the electric field and the surface area vector.

3. What is the unit of electric flux?

The unit of electric flux is volts per meter (V/m) in SI units. In other systems of measurement, it can also be expressed as newtons per coulomb (N/C) or tesla meters squared (T*m²).

4. How does electric flux change when the charge or the surface area changes?

According to Gauss's Law, electric flux is directly proportional to the amount of charge enclosed by a surface and inversely proportional to the surface area. Therefore, as the charge increases, the electric flux also increases, and as the surface area increases, the electric flux decreases.

5. Can electric flux be negative?

Yes, electric flux can be negative. This occurs when the electric field and the surface area vector are in opposite directions, resulting in a negative dot product. This can happen, for example, when the electric field is directed into a closed surface, which would result in a negative electric flux value.

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