- #1
Lolagoeslala
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Homework Statement
An electron is released from rest from the negative plate of a parallel-plate apparatus, what is the electrons speed one third of the way between the plates. It also asks for the speed at which electron will hit the positive plate if a 450 V potential difference is applied.
The Attempt at a Solution
a)
Eel = V x q
Eel = ( 450 V ) x (1.6 x 10^-19C)
Eel = 7.2 x 10^17 J
Eel = 1/2mv^2
V = √((2 x (7.2 x 10^17 J))/9.1 x 10^31Kg)
V = 1.26 x10^7 m/s
b) i don't know how to do this?