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xpsellia
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1. It has been found by experiment that the molar mass of the Rn nucleotide is 221.9703 g and that of the Po nucleotide is 217.9630 g. The molar mass of helium is 4.00150 g. Given this information, and the information from the class, calculate the energy evolved, in kJ, for the following nuclear reaction of 400.0 g of radon-222.
2. ΔE = Δmc^2 where c is speed of light
# of mol (n) = mass/molar mass
Δm = 221.9703 - (217.9630 + 4.00150)
= 5.8 x 10^-3
ΔE = 5.8 x 10^-3 (3.0 x 10^8)
= 1740000 J
n = 400.0/ 221.9703
= 1.803 mol
How do I get the energy to be kJ/mol? My teacher said the answer should be ---- x 10^8 kJ.
2. ΔE = Δmc^2 where c is speed of light
# of mol (n) = mass/molar mass
The Attempt at a Solution
Δm = 221.9703 - (217.9630 + 4.00150)
= 5.8 x 10^-3
ΔE = 5.8 x 10^-3 (3.0 x 10^8)
= 1740000 J
n = 400.0/ 221.9703
= 1.803 mol
How do I get the energy to be kJ/mol? My teacher said the answer should be ---- x 10^8 kJ.