- #1
turnip
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Homework Statement
A gas at 293.15 degrees kelvin and atmospheric pressure is compressed to a volume one fifteenth as large as its original volume and absolute pressure of 3000kPa. What is the new temperature of the gas?
Homework Equations
p1v1/t1=p2v2/t2
The Attempt at a Solution
if i rearrange the equation above for t2 i get t2=101/293.15 x 3000 x 1/15= 1.722x10-3
if i do it the wrong way and flip the divisions around so that t2=293.15 x 3000 x 1/15/101 =580.49
i take the 580 - 273 =307
307 is the right answer. perhaps i am doing it the right way, i just don't understand how this could be correct
please explain this to me