Calculating Initial Decay Rate of Ga-67 Isotope

In summary: That's what I have written in my calculation. I think the problem is in the conversion from amu to g/mol. The atomic mass of Ga-67 is 66.9282049, but the molar mass should be 66.9282049 g/mol. The difference is small, but it can make a difference in the final result.
  • #1
says
594
12

Homework Statement


An initially pure 3.4 g sample of Ga-67, an isotope with a half life of 78 hr.
What is its initial decay rate?

Note: Molar Mass values given in tables for chemical elements are for natural mix isotopic ratios. (i.e. the relative percentages of each isotope normally present in natural samples). The Molar Mass (in g/mol) for a pure isotope is equal to its atomic mass (in amu). (Answer in Bq, correct to 3 significant figures)

Avogadro's Number = 6.022045*1023 g/mol
Ga-67 = 66.9282049 u = 66.9282049 g/mol
Half-life = T1/2 = 78 Hr

Homework Equations


N = [ Avogadro's Number / 66.9282049 g/mol ] * 3.4 g
λ = ln(2) / T1/2
Decay Rate = -λ*N

The Attempt at a Solution


N = [ 6.022045*1023 g/mol / 66.9282049 g/mol ] * 3.4 g
= 3.059241321 * 1022

λ = ln(2) / 280800
= 0.00000246847

Decay Rate = 0.00000246847 * 3.059241321 * 1022
= 7.5516454*1016 Bq
= 7.55*1016 Bq (Correct to 3 sig figs)

This doesn't seem correct. I've got the atomic mass and therefore the molar mass of Ga-67, but to calculate N (nuclei) should I have subtracted the electrons from the atomic mass / molar mass?
 
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  • #2
says said:
Ga-67 = 66.9282049 u = 66.9282049 g/mol
While this is right, you are supposed to take another value: "The Molar Mass (in g/mol) for a pure isotope is equal to its atomic mass (in amu)"
The difference is large enough to influence the final result with 3 significant figures.

The electrons are fine, they are still part of the sample so there is nothing to subtract.
 
  • #3
What other value should I use for the molar mass of Ga-67? Is there a way of converting the atomic mass I have to the correct molar mass to use in this question?
 
  • #4
A sorry I misread the quoted part, somehow I thought the problem statement suggested to use 67 u as mass (not so uncommon in problems to neglect the difference between A and mass in u).
If this is an online test without limited attempts, you can try that.

I get the same answer as you so I don't know where the problem is.
 
  • #5
1 attempt only I'm afraid!

Decay Rate = -λ*N

so should it be = - 7.55*1016 Bq?
 
  • #6
Yes.
 

1. How do you calculate the initial decay rate of Ga-67 isotope?

The initial decay rate of Ga-67 isotope can be calculated by using the formula R = λN, where R is the decay rate, λ is the decay constant, and N is the number of Ga-67 atoms present.

2. What is the decay constant of Ga-67 isotope?

The decay constant of Ga-67 isotope is 0.0000000000921 per second. This value is constant and specific to each isotope.

3. How do you determine the number of Ga-67 atoms present?

The number of Ga-67 atoms present can be determined by using the Avogadro's number (6.022 x 10^23) and the mass of the sample in grams. The formula for this is N = (m/M) x (N_A), where N is the number of atoms, m is the mass of the sample, M is the molar mass of Ga-67, and N_A is the Avogadro's number.

4. What units are used to measure the decay rate of Ga-67 isotope?

The decay rate of Ga-67 isotope is measured in units of becquerels (Bq) or curies (Ci). 1 Bq is equal to 1 decay per second, while 1 Ci is equal to 3.7 x 10^10 decays per second.

5. Can the initial decay rate of Ga-67 isotope change over time?

No, the initial decay rate of Ga-67 isotope remains constant over time. However, the total decay rate may decrease as the number of Ga-67 atoms present decreases due to radioactive decay.

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