Calculating Normal Force of Log on Bullfrog

[rebeccc]

A second 0.63 bullfrog is on a log tilted 33 above horizontal. How large is the normal force of the log on this bullfrog?

 

[danago]

Is that meant to read 0.63kg?

What have you tried?

 

[baba89]

To calculate the normal force of the log on the bullfrog, we need to use the equation F=ma, where F is the force, m is the mass, and a is the acceleration. In this case, the force we are trying to find is the normal force, which is the force perpendicular to the surface of the log. We can also use the equation F=mg, where g is the acceleration due to gravity (9.8 m/s^2).

First, we need to determine the mass of the bullfrog. Let's assume that the average mass of a bullfrog is 0.25 kg. Next, we need to determine the acceleration of the bullfrog on the tilted log. Since the log is tilted at an angle of 33 degrees above horizontal, we can use trigonometry to determine the component of gravity acting on the bullfrog. The component of gravity perpendicular to the surface of the log would be mgcos(33). Plugging in the values, we get:

F = (0.25 kg)(9.8 m/s^2)cos(33) = 2.03 N

Therefore, the normal force of the log on the bullfrog is approximately 2.03 Newtons. This means that the log is exerting a force of 2.03 N perpendicular to its surface to keep the bullfrog from falling off.