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chemnoob.
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Homework Statement
By what factor would the rate of a reaction for which the activation energy is 159 kJ be increased by a temperature rise of 10degreesC from 25 to 35degreesC?
Temperature is directly proportional to reaction rate. As temperature increases, the particles in a reaction have more kinetic energy, which leads to more frequent and energetic collisions. This increases the chances of successful collisions and therefore increases the reaction rate.
Increasing temperature decreases the activation energy required for a reaction to occur. This is because at higher temperatures, more particles have enough energy to surpass the activation energy barrier, making it easier for the reaction to take place.
The equation for calculating reaction rate is: rate = k[A]^m[B]^n, where k is the rate constant, [A] and [B] are the concentrations of the reactants, and m and n are the reaction orders. To calculate the rate increase with a temperature rise of 10°C, you would use the equation: new rate = old rate x 2^(10/T), where T is the original temperature in Kelvin.
No, reaction rate does not continue to increase indefinitely as temperature increases. At some point, the reaction will reach its maximum rate and will not increase any further. This is because at very high temperatures, the rate of the reverse reaction may become comparable to the rate of the forward reaction, resulting in a constant overall rate.
The effect of temperature on reaction rate varies depending on the type of reaction. Generally, exothermic reactions (reactions that release heat) will have a greater increase in rate with temperature compared to endothermic reactions (reactions that absorb heat). This is because the increase in temperature will provide additional energy to overcome the activation energy barrier for exothermic reactions, but may actually decrease the rate of endothermic reactions as more energy is needed to overcome the barrier.