Post your working out. We have no way of knowing where you went wrong (and therefore how to help you/ correct any mistakes) if we can't see your reasoning, but the attempt at the problem appears to be right (eliminate the short wire and simplify using the rules for resistors in series/ parallel).Arka420 said:Homework Statement
: Given the circuit diagram, find the equivalent resistance between points P and Q.[/B]
Homework Equations
: ΔVloop = 0, ΔIjunction = 0 and V = IR[/B]The Attempt at a Solution
: Eliminating the wires with no resistors and solving for resistance gives me the answer as (11/10) R, which is not the answer. I'm confused as to which resistors are in parallel and which resistors are in series. [/B]
Not correct.Arka420 said:This is how I worked out the circuit. Is it correct?
CWatters said:
Equivalent resistance is the measure of a single resistor that would produce the same effect as multiple resistors connected in a circuit.
In a circuit, resistors are often connected in series or parallel. Calculating the equivalent resistance allows us to simplify the circuit and determine the overall resistance of the circuit.
In a series circuit, the equivalent resistance is equal to the sum of all the individual resistances. It can be calculated by adding the values of all the resistors in the circuit.
In a parallel circuit, the equivalent resistance is less than the smallest individual resistance. It can be calculated using the formula 1/Req = 1/R1 + 1/R2 + ... + 1/Rn, where Req is the equivalent resistance and R1, R2, etc. are the individual resistances.
If equivalent resistance is not calculated correctly, it can lead to incorrect calculations of current and voltage in a circuit. This can result in unexpected performance or damage to the circuit components.