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chongj12
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This problem was discussed in my calculus 3 class, and there is one step that I don't understand.
An object of mass m travels along the parabola y = x[tex]^{2}[/tex] with a constant speed of 10 units/sec. What is the force on the object due to its acceleration at (0,0) (write the answer in terms of unit vectors i,j,k)? (this problem is from Thomas' calculus 11th edition, section 13.5 #20)
f(x) = x[tex]^{2}[/tex]
a = atT + anN
at = d(|v|)/dt
an = [tex]kappa[/tex]|v|[tex]^{2}[/tex]
T = v/|v|
[tex]kappa[/tex] = |f''(x)|/((1+f'(x)[tex]^{2}[/tex])[tex]^{3/2}[/tex])
r = ti + t[tex]^{2}[/tex]j
=> v = i+2tj
=> |v| = (1+4t[tex]^{2}[/tex])[tex]^{1/2}[/tex]
N = (d(T)/dt)/(|d(T)/dt|)3. The Attempt at a Solution **** this was the solution presented in class:
at = 0 because d(10)/dt = 0
an = 100[tex]kappa[/tex]
[tex]kappa[/tex] = 2 at the point (0,0)
*******T = 1/((1+4t[tex]^{2}[/tex])[tex]^{1/2}[/tex]) (i+2tj)
T = i at the point (0,0)
N = j at the point (0,0)
=> F = ma = m(200)jThe step that I don't understand is marked with stars (Deriving T). Since the speed is given as 10 units/sec, shouldn't that be used as |v| rather than (1+4t[tex]^{2}[/tex])[tex]^{1/2}[/tex]? And if |v| = (1+4t[tex]^{2}[/tex])[tex]^{1/2}[/tex], doesn't this contradict the problem statement, which says that speed is constant? This makes little sense to me because we used different values for |v| throughout the problem
Homework Statement
An object of mass m travels along the parabola y = x[tex]^{2}[/tex] with a constant speed of 10 units/sec. What is the force on the object due to its acceleration at (0,0) (write the answer in terms of unit vectors i,j,k)? (this problem is from Thomas' calculus 11th edition, section 13.5 #20)
Homework Equations
f(x) = x[tex]^{2}[/tex]
a = atT + anN
at = d(|v|)/dt
an = [tex]kappa[/tex]|v|[tex]^{2}[/tex]
T = v/|v|
[tex]kappa[/tex] = |f''(x)|/((1+f'(x)[tex]^{2}[/tex])[tex]^{3/2}[/tex])
r = ti + t[tex]^{2}[/tex]j
=> v = i+2tj
=> |v| = (1+4t[tex]^{2}[/tex])[tex]^{1/2}[/tex]
N = (d(T)/dt)/(|d(T)/dt|)3. The Attempt at a Solution **** this was the solution presented in class:
at = 0 because d(10)/dt = 0
an = 100[tex]kappa[/tex]
[tex]kappa[/tex] = 2 at the point (0,0)
*******T = 1/((1+4t[tex]^{2}[/tex])[tex]^{1/2}[/tex]) (i+2tj)
T = i at the point (0,0)
N = j at the point (0,0)
=> F = ma = m(200)jThe step that I don't understand is marked with stars (Deriving T). Since the speed is given as 10 units/sec, shouldn't that be used as |v| rather than (1+4t[tex]^{2}[/tex])[tex]^{1/2}[/tex]? And if |v| = (1+4t[tex]^{2}[/tex])[tex]^{1/2}[/tex], doesn't this contradict the problem statement, which says that speed is constant? This makes little sense to me because we used different values for |v| throughout the problem
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