Can a Claw Design Hold a Spinning Ball Against Centripetal Force?

In summary, the conversation discusses a robotics engineering problem involving a robot with a centripetal arm that launches a foam basketball. The arm needs to rotate at 468 RPM with 19 ft/sec acceleration, 15 N force, and a torque of 684 oz-in. The team also discusses the design of a claw to hold the ball in place against the centripetal force, and the need for a normal force to prevent the ball from flying out tangentially. The team also considers using a flywheel and hopper as an alternative solution.
  • #1
physicsofme
5
0
Hi guys and gals, I have a robotics related engineering problem I need help with.

So, for our robot we are building, it has a centripetal arm that launches a foam basketball. The arm is 2 foot in diameter rotating from the center with 3 pounds on each side (including projectile and counterweight). It is also shooting up to 60 feet away and 6 foot high. So that comes out to needing 468 RPM with 19 ft/sec acceleration, 15 N force, a required torque of 684 oz-in with 10 spin up rotations that releases after 2.5 seconds.

So basically the centripetal force is 232.449 N and the centripetal acceleration is 732.089 M/s^2.

So for our claw design, it's three different welded chain links to form fit the ball with a urethane fingertip to add friction between the urethane ball. But how can we calculate the required torque of the three servos (one on each chain piece) that's needed to hold the ball in place against the centripetal force? It also needs to be able to release fast enough. Is the centripetal force too much for any servo? or what? We're very confused. Please help :(
 
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  • #2
looks like centrifugal force to me - the servo is not seeing an inertial reference frame - by your calcs you need the servos to be able to hold on to 75kgs ... which seems a bit excessive to me. Mind you, I've never had to throw a 3lb ball 60ft.
 
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  • #3
Aside: have you considered putting the ball in a cup with the opening perpendicular to the arm so the acceleration holds the ball in place - releasing the ball involves stopping the arm abruptly ... say your servo pushes a barrier of some sort in the way, at the correct angle, as the arm comes around on the tenth turn? (You'll probably want the same action to disconnect the motor driving the arm too.) This way the servo does not have to be strong enough to hold the ball.

Of course this assumes that throwing the ball is all the robot has to do.
If you must have a hand, then you only need one servo-finger... and only that one needs to form-fit the ball.
 
  • #4
Well it does have to have a hand to receive the ball from another hand, and we went over the abrupt release but we fear damaging our robot, which is a high probability with such speeds. The ball is actually 11.2 ounces and the rest of the arm is a little more than 2 pounds if that helps. And that's just one side of the arm, the other side has the same counterweight as the first side with the ball.

So also, is there a way to create a claw piece that would be able to act as a normal force for the ball while spinning because the centripetal force would also push it towards the outside so if it were balanced correctly, it would still remain towards the outside? Then would it still need 75 kg force to open up?
 
  • #5
So also, is there a way to create a claw piece that would be able to act as a normal force for the ball while spinning
Yes. Hard to describe ... consider: on release, the ball wants to fly perpendicular to the arm.

Make two stiff fingers in a kind of claw so they curl over the ball stopping it from moving radially. You'll need to experiment a bit so the ball will still slip out tangentially if it is not restrained. Then you just need a servo thumb to hold the ball in place. Should require almost nothing to hold it in place.

If you were sitting on the hand holding the ball, it would feel like you were holding a grown man against gravity. I suspect this is the reason machines for throwing balls are usually a flywheel and a hopper.

note: centripetal force pulls everything towards the center.
 

1. What is the difference between centripetal force and torque?

Centripetal force is the force that acts towards the center of a circular path, keeping an object in circular motion. Torque, on the other hand, is a rotational force that causes an object to rotate around an axis.

2. How are centripetal force and torque related?

Centripetal force and torque are related in that they both involve forces acting on a rotating object. Torque is necessary for an object to rotate, and centripetal force is necessary to keep the object in circular motion.

3. Can an object have both centripetal force and torque acting on it?

Yes, an object can have both centripetal force and torque acting on it at the same time. For example, in a spinning top, there is both a force acting towards the center (centripetal force) and a force causing the top to rotate (torque).

4. How do you calculate centripetal force and torque?

To calculate centripetal force, you can use the equation F = mv^2/r, where m is the mass of the object, v is the velocity, and r is the radius of the circular path. To calculate torque, you can use the equation T = Fr, where F is the force applied and r is the distance from the axis of rotation.

5. What are some real-life examples of centripetal force and torque?

Centripetal force can be observed in phenomena such as the Earth's orbit around the sun, the rotation of a Ferris wheel, or the motion of a car on a curved road. Torque can be seen in the rotation of a bicycle wheel, the movement of a door on its hinges, or the spin of a figure skater on ice.

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