- #1
eljose
- 492
- 0
let be the solution to SE in the form [tex]\psi=exp(iS/\hbar)[/tex] where S has the "exact" differential equation solution in the form:
[tex]\frac{dS}{dt}+\frac{1}{2m}(\nabla{S})^{2}+V(x)-\frac{i\hbar}{2m}(\nabla^{2}{S}) [/tex]
then we could form the complex potential:[tex]U=V(x)-\frac{i\hbar}{2m}(\nabla^{2}{S})[/tex]
and the Classical equation of Motion in the form:
[tex]m\frac{d^{2}x}{dx^{2}}=-\nabla{U} [/tex]
How do we solve equation (1)?...for example we use a trial function for S=f(r,t) then we calculate [tex]\nabla^{2}{f(r,t)[/tex] and introduce it into equation (1),solve S for this function f(r,t) and again we introduce into the differential equation to find another value of S more accurate than before.
Complex trajectories...are they allowed?..remember that the particle can be into a "classical forbidden" region,then if we use the eikonal equation of Optics [tex](\nabla{S})^{2}=n^{2} [/tex] with n the refraction index of the material we would find for our particle that n would be complex so the "rays of light" trajectories of the particle,can go inside the potential barrier...
[tex]\frac{dS}{dt}+\frac{1}{2m}(\nabla{S})^{2}+V(x)-\frac{i\hbar}{2m}(\nabla^{2}{S}) [/tex]
then we could form the complex potential:[tex]U=V(x)-\frac{i\hbar}{2m}(\nabla^{2}{S})[/tex]
and the Classical equation of Motion in the form:
[tex]m\frac{d^{2}x}{dx^{2}}=-\nabla{U} [/tex]
How do we solve equation (1)?...for example we use a trial function for S=f(r,t) then we calculate [tex]\nabla^{2}{f(r,t)[/tex] and introduce it into equation (1),solve S for this function f(r,t) and again we introduce into the differential equation to find another value of S more accurate than before.
Complex trajectories...are they allowed?..remember that the particle can be into a "classical forbidden" region,then if we use the eikonal equation of Optics [tex](\nabla{S})^{2}=n^{2} [/tex] with n the refraction index of the material we would find for our particle that n would be complex so the "rays of light" trajectories of the particle,can go inside the potential barrier...
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