Can someone answer this easy phsyics problem about vertical height

In summary: Well since he is jumping upwards he only takes half of the time to get to his maximum height. Therefore the rest of the time is spent coming down. Hence no need for the time coming down.
  • #1
Casey314stl
15
0

Homework Statement

A basketball player achieves a hang time of 0.978 s in dunking the ball.
What vertical height will he attain? The
acceleration of gravity is 9.8 m/s^2

Answer in units of m

Homework Equations


?

The Attempt at a Solution

9.8/0.978^2= 10.245

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
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  • #2
Yes. You can.

We do not (can not) do homework for you. Show your work, we can help.
 
  • #3
The attempt at a solution 9.8/0.978^2= 10.245
 
  • #4
Casey314stl said:
The attempt at a solution 9.8/0.978^2= 10.245

Remember that H=.5gt^2

Retry and see what you get.
 
  • #5
DaveC426913 said:
Yes. You can.

We do not (can not) do homework for you. Show your work, we can help.

I tried H=.5*g*t^2 and got 4.68677?
 
  • #6
22.9653?
 
  • #7
Casey314stl said:
I tried H=.5*g*t^2 and got 4.68677?

Remember that time going up = time coming down .
 
  • #8
Casey314stl said:
22.9653?

No since t(up)=t(down)

then: H=.5g*(t/2)^2
 
  • #9
mtayab1994 said:
Remember that time going up = time coming down .

what?
 
  • #10
mtayab1994 said:
No since t(up)=t(down)

then: H=.5g*(t/2)^2

Thanks a lot I got it but why is it half time^2?
 
  • #11
When you have the time going up = time going down, then you have: t(up)=t(down)=.978/2

I'm helping you too much.
 
  • #12
mtayab1994 said:
When you have the time going up = time going down, then you have: t(up)=t(down)=.978/2

I'm helping you too much.

I already got the the answer from the last response I was just wonder why it was half the time^2 if that was for every problem for this equation or just if an object is traveling up?
 
  • #13
Casey314stl said:
I already got the the answer from the last response I was just wonder why it was half the time^2 if that was for every problem for this equation or just if an object is traveling up?

Well since he is jumping upwards he only takes half of the time to get to his maximum height. Therefore the rest of the time is spent coming down. Hence no need for the time coming down.
 

1. How do I calculate the vertical height in a physics problem?

To calculate the vertical height in a physics problem, you can use the formula h = v2 / 2g, where h is the vertical height, v is the initial velocity, and g is the acceleration due to gravity. Make sure to use consistent units for all variables.

2. What is the acceleration due to gravity?

The acceleration due to gravity, denoted by the letter g, is a constant value of 9.8 m/s2 on Earth. This value is used in the formula for calculating vertical height and is affected by the mass and distance between two objects.

3. Can I use this formula for any object falling?

The formula for calculating vertical height can be used for any object falling under the influence of gravity, as long as there is no air resistance. However, for objects with a non-negligible size or shape, other factors may need to be taken into account.

4. How does air resistance affect the calculation of vertical height?

When an object falls through the air, air resistance creates an opposing force that slows down the object's motion. This means that the object will not reach the calculated vertical height due to the reduction in velocity. In such cases, a more complex formula or experimental data may be needed to accurately calculate the vertical height.

5. Is there a simpler way to calculate the vertical height?

For simple physics problems, the formula h = v2 / 2g may be the easiest way to calculate the vertical height. However, for more complex problems, it may be helpful to break down the problem into smaller steps and use other formulas or methods to find the vertical height.

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