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Homework Statement
Let (xn)n[itex]\in[/itex]ℕ and (yn)n[itex]\in[/itex]ℕ be Cauchy sequences of real numbers.
Show, without using the Cauchy Criterion, that if zn=xn+yn, then (zn)n[itex]\in[/itex]ℕ is a Cauchy sequence of real numbers.
Homework Equations
The Attempt at a Solution
Here's my attempt at a proof:
Let (xn) and (yn) be Cauchy sequences. Let (zn) be a sequence and let zn=xn+yn.
Since (xn) and (yn) are Cauchy, [itex]\exists[/itex]N[itex]\in[/itex]ℕ such that,
|xn-xm|<ε/2, and
|yn-ym|<ε/2 for n,m≥N.
Let n,m≥N and let zn,zm[itex]\in[/itex](zn).
Then,
|zn-zm|=|xn-xm|+|yn-ym|
<ε/2+ε/2=ε.
Therefore,
|zn-zm|<ε for all n,m≥N and hence, (zn) is a Cauchy sequence of real numbers.
Is this correct?
Any input is appreciated.
Thanks.