- #1
Jaimie
- 35
- 0
If f is a differntiable function, find the expression for derivatives of the following functions.
a) g(x)= x/ f(x)
b) h(x) [f(x^3)]^2
c) k(x)= sqrt (1 + [f(x)]^2)
First off, I am not even sure what they are asking. I am assuming that they want the derivative for each component of the equation? then to find the derivative for the entire function?
a) really not sure about this one
b) g(x) = x^2 f(x)= x^3
g'(x)= 2x f'(x)= 3x^2
h'(x)= 2(x^3)(3x^2)
h'(x)= (2x^3)(3x^2)
h'(x)= 6x^5
c) g(x)= sqrt (x) h(x)= 1 + x^2
g'(x)= 1/2 x^-1/2 h'(x)= 2x
f'(x)= 1
k'(x)= 1/2 1 + (x^2)^-1/2(2x)
then continue to find equation.
The fact that f(x) is in the equation is throwing me off. Can you explain why you are approaching the problem this way. I am doing my best but we were given this yesterday to solve, but without understanding the question, I am a little at a loss. Thank you so much!
a) g(x)= x/ f(x)
b) h(x) [f(x^3)]^2
c) k(x)= sqrt (1 + [f(x)]^2)
First off, I am not even sure what they are asking. I am assuming that they want the derivative for each component of the equation? then to find the derivative for the entire function?
a) really not sure about this one
b) g(x) = x^2 f(x)= x^3
g'(x)= 2x f'(x)= 3x^2
h'(x)= 2(x^3)(3x^2)
h'(x)= (2x^3)(3x^2)
h'(x)= 6x^5
c) g(x)= sqrt (x) h(x)= 1 + x^2
g'(x)= 1/2 x^-1/2 h'(x)= 2x
f'(x)= 1
k'(x)= 1/2 1 + (x^2)^-1/2(2x)
then continue to find equation.
The fact that f(x) is in the equation is throwing me off. Can you explain why you are approaching the problem this way. I am doing my best but we were given this yesterday to solve, but without understanding the question, I am a little at a loss. Thank you so much!