- #1
mybrohshi5
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Homework Statement
A chain consisting of two links, each of mass 0.5 kg, is lifted vertically with an acceleration of 3.0 m/s2 upward.
The magnitude of the downward force exerted on the top link by the bottom link is?
Homework Equations
F = ma
The Attempt at a Solution
1 is the top link
2 is the bottom link
F1,2 = The force on 1 by 2
The Fnet on either of the two links is (0.5kg)(3m/s2) = 1.5N
so
Fnet = Fpull - Fg - F1,2
Fpull = 1kg(3m/s2) = 3N
so
1.5N = 3N - (.5kg)(9.8m/s2) - F1,2
F1,2 = 3.4 N downward
The answer is 6.4N but i don't understand why? where did i go wrong?
this is exactly what i did on a homework assignment and got it right but this is what i did on the test and i got it wrong since the answer is 6.4N not 3.4N like i got.
Thanks for any help