- #1
Othman0111
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Homework Statement
Homework Equations
The Attempt at a Solution
I'm sure my solution is wrong because of Φ(z=0) ≠ 0
I searched the internet for a similar problem but I couldn't. Any help will be appreciated.
Each mirror image charge in one plate needs to be mirrored in the other plate, leading to an infinite series.Othman0111 said:Homework Statement
View attachment 240018
Homework Equations
View attachment 240020
The Attempt at a Solution
View attachment 240019
I'm sure my solution is wrong because of Φ(z=0) ≠ 0
I searched the internet for a similar problem but I couldn't. Any help will be appreciated.
haruspex said:Each mirror image charge in one plate needs to be mirrored in the other plate, leading to an infinite series.
http://physicspages.com/pdf/Griffiths%20EM/Griffiths%20Problems%2003.35.pdfOthman0111 said:Can you tell me the series or how the answer look like
The charge between two conductors refers to the amount of electric charge that is present on each of the two conductors. This charge is determined by the properties of the conductors and the surrounding environment.
The charge between two conductors can be calculated using Coulomb's Law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The method of image charges is a technique used to solve problems involving conductors in the presence of a charge. It involves creating a mirror image of the charge on the other side of the conductor to simplify the problem and find the electric field and potential.
The method of image charges is most useful when dealing with conductors in the presence of a point charge or a charged plane. It simplifies the problem by reducing it to a single charge and its mirror image, allowing for easier calculation of the electric field and potential.
The method of image charges is limited to problems involving conductors and point charges or charged planes. It also assumes that the conductors are perfect and have no imperfections or irregularities. Additionally, it cannot be used for problems involving multiple charges or complex geometries.