Chinese Remainder Theorem: Divisibility in Arithmetic

In summary, divisibility is the ability to divide one number by another number without any remainder. The divisibility rule for 2 states that a number is divisible by 2 if the last digit of the number is even (0, 2, 4, 6, or 8). The divisibility rule for 3 states that a number is divisible by 3 if the sum of its digits is divisible by 3. The divisibility rule for 5 states that a number is divisible by 5 if the last digit of the number is either 0 or 5. The divisibility rule for 9 states that a number is divisible by 9 if the sum of its digits is divisible by 9.
  • #1
mtayab1994
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Chinese remainder theorem help

Homework Statement



Solve in [tex]Z^{2}:6x-5y=1[/tex]

Conclude the solution to the system:

X≡2(mod5) , X≡1(mod6)

The Attempt at a Solution



1- solved the equation and found one unique solution which was S={(1,1)}

Given:
X≡2(mod5) , X≡1(mod6)

X≡2(mod5) means X=5t+2

X≡1(mod6) means 5t+2=1(mod6) which is 5t=-1(mod6) But how can i proceed from here on?
 
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  • #2
Solved it :)
 

What is divisibility?

Divisibility is the ability to divide one number by another number without any remainder. In other words, if a number is divisible by another number, then when you divide the first number by the second number, you get a whole number as the result.

What is the divisibility rule for 2?

The divisibility rule for 2 states that a number is divisible by 2 if the last digit of the number is even (0, 2, 4, 6, or 8).

What is the divisibility rule for 3?

The divisibility rule for 3 states that a number is divisible by 3 if the sum of its digits is divisible by 3.

What is the divisibility rule for 5?

The divisibility rule for 5 states that a number is divisible by 5 if the last digit of the number is either 0 or 5.

What is the divisibility rule for 9?

The divisibility rule for 9 states that a number is divisible by 9 if the sum of its digits is divisible by 9.

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